How to compare 2 courses using Review schema within Course Schema?

#613446
  • Resolved Anonymous

    2 years, 2 months ago

    Rank Math free

    Hi, I want to know that Is it possible to compare 2 courses using review Schema within Course Schema? Can you generate one template for this page https://www.ptpioneer.com/ace-vs-nasm/. I think we have to place both the courses in one Course Schema and then address Positive and Negative note of Review Schema for comparing both courses within the single Course Schema. Can you make one template and show me so that I can know how to do it for the rest?

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  • Jeremy

    2 years, 2 months ago

    Hello,

    Thank you so much for getting in touch.

    We do have a Course schema where you can add reviews but if this requires customization, you can customize it further using our Schema Builder.

    You can create a custom schema using the Rank Math Schema Generator:
    https://rankmath.com/kb/schema-generator/

    Use the properties from https://schema.org/Course and https://schema.org/Review, once the schema is created, save the Schema, go to the Code Validation tab, and test it: https://validator.schema.org/

    The validator should also be able to pick up duplicate properties if there are properties that are the same with each schema template. However, you should be able to compare the two templates and don’t use the same properties twice.

    Please note that creating your custom Schema is only available for the PRO subscription.

    Hope that helps and please do not hesitate to let us know if you need my assistance with anything else.

    RankBot

    2 years, 1 month ago

    Hello,

    Since we did not hear back from you for 15 days, we are assuming that you found the solution. We are closing this support ticket.

    If you still need assistance or any other help, please feel free to open a new support ticket, and we will be more than happy to assist.

    Thank you.

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The ticket ‘How to compare 2 courses using Review schema within Course Schema?’ is closed to new replies.